What is the mass of #9.25 times 10^22# molecules of water?

Answer 1

27.72g

A mole of any compound has a mass equal to the compound's relative formula mass in grams. So, the first step is to work out how many moles of the substance there is. There are #6.022×10^23# molecules in a mole of a substance, so to find out how many moles there are of water, divide #9.25xx10^23# by #6.022×10^23# which is 1.5360345... or #1.54# to 3 significant figures.

So we have 1.54 moles of water.

Next, we need to find the relative formula mass of water using the relative atomic masses of the atoms making it up. Water is #H_2O# so we have 2 hydrogens (atomic mass 1) and 1 oxygen (atomic mass 16). #(2xx1)+16 = 18# so water has a relative formula mass of 18.

Now we remember the rule about moles and multiply 18 by our 1.54 moles to get 27.72g (27.7 to 3SF)

Hope this helps; let me know if I can do anything else:)

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Answer 2

#27.72# #"g"#

The relationship between the number of particles and the number of mole of a substance is given by the equation #N = n L#; where #N# is the number of particles, #n# is the number of mole, and #L# is Avogadro's constant.
#n# is also defined using the equation #n = frac(m)(M)#; where #m# is the mass and #M# is the molar mass of the substance.
Let's substitute the definition of #n# into the first equation:
#Rightarrow N = n L#
#Rightarrow N = frac(m)(M) times L#
Then, let's substitute the value of #N# and #L# into the equation:
#9.25 times 10^(22) = frac(m)(M) times 6.02 times 10^(23)#

Let's now assess water's molar mass:

#Rightarrow M(H_(2)O) = 2 times 1.00 + 16.0#
#Rightarrow M(H_(2)O) = 2.00 + 16.00#
#Rightarrow M(H_(2)O) = 18.00#

Adding the following to the formula:

#Rightarrow 9.25 times 10^(22) = frac(m)(18.00) times 6.02 times 10^(23)#
Dividing both sides of the equation by #6.02 times 10^(23)#:
#Rightarrow 1.54 = frac(m)(18.00)#
Multiplying both sides by #18.00#:
#Rightarrow 27.72 = m#
#therefore m = 27.72#
Therefore, the mass of #9.25 times 10^(22)# molecules of water is #27.72# #"g"#.
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Answer 3

The mass of 9.25 x 10^22 molecules of water is approximately 30.6 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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