What is the mass of #4.49*10^25# particles of #HCl#?

Answer 1

#"Number of HCl particles"/"Number of HCl particles per mol"# #xx36.5*g*mol^-1# #=# #??#

It is a fact that #6.022xx10^23# individual #HCl# particles have a mass of #36.5# #g#. This is simply another way of saying that the molar mass of #HCl#, the mass of #"Avogadro's Number"# of #HCl# particles, is #36.5*g*mol^-1#.

To calculate the number of moles, simply divide the given number by Avogadro's number, and then multiply the result by the molar mass:

#"Number of HCl particles"/"Number of HCl particles per mol"# #xx36.5*g*mol^-1# #=# #(4.49xx10^25)/(6.022xx10^23)# #xx# #36.5*g# #=# #??# #g#

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Answer 2

Axel Alvarado

In order to calculate the mass of 4.49 x 10^25 HCl particles, you must first calculate the molar mass of HCl, which is approximately 36.46 grams per mole. Next, you must convert the number of particles to moles using Avogadro's number, which is 6.022 x 10^23 particles per mole. Finally, multiply the moles by the molar mass to obtain the mass in grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.