What is the mass of #3.54*10^24# molecules of rubidium oxide?

Answer 1

It is a fact that #N_A# #Rb_2O# particles have a mass of #186.94*g#.

Given that #6.02214xx10^24# formula units of #Rb_2O# have a mass of #186.94*g#, the given number of #Rb_2O# formula units have a mass of:

#(3.54xx10^24" formula units of " Rb_2O)/(6.02214xx10^24" formula units "mol^-1*Rb_2O)#

#=#

#??" moles of rubidium oxide" #

So the mass #~=# #1/2# #mol# #xx186.94*g*mol^-1, "i.e. "93*g#.

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Answer 2

Cooper Anderson

Rubidium oxide (Rb₂O) has a molar mass of about 186.94 g/mol, and 3.54*10^24 molecules have a mass of about 1.048 x 10^3 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.