What is the mass of # 2.70\times 10^22# tungsten atoms?

Answer 1

Well we know that #6.022xx10^23# tungsten atoms have a mass of #183.8*g#.

Do we know this? Well, it is written on the Periodic Table, which you must have beside you. We specify here a molar quantity, i.e. Avogadro's number, of tungsten atoms......

And so we take the product of the quotient....

#"Mass of metal"=(2.70xx10^22*"tungsten atoms")/(6.022xx10^23*"tungsten atoms"*mol^-1)xx183.8*g*mol^-1=??*g#
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Answer 2

The mass is approximately 114 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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