What is the mass, in grams, of a single iridium atom (#m_Ir = "192.22 u"#)?

Answer 1

#3.1920 * 10^(-22)"g"#

The idea here is that you need to use the definition of the unified atomic mass unit, #"u"#, to determine the mass of an iridium atom in grams.
The unified atomic mass unit is defined as #1/12# of the mass of a neutral unbound atom of carbon-12 and is equivalent to #"1 g mol"^(-1)#.

I won't go into the calculation here, but keep in mind that this is how the conversion factor from unified atomic mass units to grams per mole looks.

#"1 u" = "1 g mol"^(-1)#
In your case, the mass of a single iridium atom is said to be equal to #"192.22 u"#. This means that the molar mass of iridium will be equal to
#192.22 color(red)(cancel(color(black)("u"))) * "1 g mol"^(-1)/(1color(red)(cancel(color(black)("u")))) = "192.22 g mol"^(-1)#

Lastly, to convert between the mass of a single iridium atom and the mass of a mole of iridium atoms, use Avogadro's number.

#"192.22 g"color(red)(cancel(color(black)("mol"^(-1)))) * overbrace((1color(red)(cancel(color(black)("mol"))))/(6.022 * 10^(23)"atoms"))^(color(brown)("Avogadro's number")) = color(green)(3.1920 * 10^(-22)"g")#

Five sig figs are used to round the result.

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Answer 2

The mass of a single iridium atom is approximately 192.22 atomic mass units (u). To convert atomic mass units to grams, you can use the conversion factor: 1 u = 1.66054 x 10^-24 grams. So, the mass of a single iridium atom in grams is approximately 3.187 x 10^-22 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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