What is the mass, in grams, of 2.50 moles of iron(II) hydroxide, #Fe(OH)_2#?
The mass of
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To find the mass of 2.50 moles of iron(II) hydroxide (Fe(OH)2), you need to multiply the number of moles by the molar mass of Fe(OH)2.
The molar mass of Fe(OH)2 can be calculated as follows: Fe: 1 atom * 55.845 g/mol = 55.845 g/mol O: 2 atoms * 16.00 g/mol = 32.00 g/mol H: 2 atoms * 1.008 g/mol = 2.016 g/mol
Total molar mass = 55.845 g/mol + 32.00 g/mol + 2.016 g/mol = 89.861 g/mol
Now, multiply the number of moles by the molar mass: 2.50 moles * 89.861 g/mol = 224.6525 g
So, the mass of 2.50 moles of iron(II) hydroxide is approximately 224.65 grams.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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