What is the mass in grams of #1.02 * 10^24# atoms manganese?

Answer 1

One mole of stuff represents #6.022140857(74)xx10^23# individual items of that stuff.

#1# #mol# of manganese has a mass of #54.94*g#. Thus, #"Mass"# #=(1.02xx10^24" atoms manganese")/(6.022xx10^24" atoms of manganese "mol^-1)xx54.94*g*mol^-1#

#~=9.0*g#

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Answer 2

Cooper Anderson

Manganese has a mass of 1.02 × 10^24 atoms, or roughly 54.93 grams.

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Answer 3

Mateo Aguilar

To find the mass in grams of 1.02 × 10^24 atoms of manganese, we need to use the concept of molar mass and Avogadro's number. First, we find the molar mass of manganese, which is approximately 54.94 grams per mole. Then, we divide the number of atoms by Avogadro's number to find the number of moles. Finally, we multiply the number of moles by the molar mass to find the mass in grams.

The calculation is as follows: 1.02 × 10^24 atoms Mn × (1 mole Mn / 6.022 × 10^23 atoms Mn) × (54.94 grams Mn / 1 mole Mn)

After performing the calculation, we find that the mass of 1.02 × 10^24 atoms of manganese is approximately 9.11 × 10^1 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.