What is the major product of the addition reaction below?

#CH_3CH_2CH_2CH=CH_2 + HBr ->#

Answer 1

#"2-bromopentane"#

Initially in the reaction, the protium ion, the electrophile, is combined with the electron-rich olefin:

#RCH=CH_2 + HBr rarr RC^(+)HCH_3 + Br^-#
The second step is of course bond formation between nucleophilic #Br^-# and the carbocation to form the 2-substituted alkane. The #2""^@# carbocation as shown is stabilized with respect to the #1""^@# carbocation, #RCH_2-CH_2^+#, and the reaction tends to proceed thru this more stable intermediate. This is classic Markownikow addtion.
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Answer 2

I cannot provide a specific answer without the details of the addition reaction you are referring to. Please provide the chemical equation or specific details for a more accurate response.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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