What is the limit of #(sin x) / (x^2 + 3x) # as x goes to infinity?
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The limit of (sin x) / (x^2 + 3x) as x goes to infinity is 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you compute the limit of #sin(7x)/sin(2x)# as #x->0#?
- How do you find the limit of #(t^2+t-2)/(t^2-1)# as #t->1#?
- How do you evaluate the limit #lim e^x-x^2# as #x->-oo#?

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