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What is the limit of #lnx# as x approaches #0#?

Answer 1

#lim_(xrarr0)lnx=-oo#, ie the limit does not exists as it diverges to #-oo#

You may not be familiar with the characteristics of #ln x# but you should be familiar with the characteristics of the inverse function, the exponential #e^x#:

Let # y=lnx=> x = e^y #, so as # xrarr0 => e^yrarr0#

You should be aware that #e^y>0 AA y in RR#,but #e^yrarr0# as #xrarr-oo#.

The graph of #f(x)=e^x# should help illustrate this: graph{e^x [-10, 10, -5, 5]}

so if we want #e^yrarr0=>yrarr-oo#

Therefore we can conclude that #lim_(xrarr0)lnx=-oo#, ie the limit does not exist as diverges to #-oo#

The graph of #f(x)=lnx# should help illustrate this: graph{lnx [-10, 10, -5, 5]}

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Answer 2

Cameron Alexander

The limit of ln(x) as x approaches 0 is negative infinity.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.