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What is the limit of #(8-(7y^2))/((2y^2)+9y)# as x goes to infinity?

Answer 1

AS #y# goes greater and greater, #y^2# goes greater at a very much faster rate.

So further on, the #8# above the bar and the #9y# make less and less of a difference, and the function will get nearer and nearer to #(-7cancel(y^2))/(2cancel(y^2))=-3 1/2#

Or, in "the language":

#lim_(y->oo) (8-7y^2)/(2y^2+9y) =-3 1/2#

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Answer 2

Samantha Adkison

The limit of (8-(7y^2))/((2y^2)+9y) as y goes to infinity is -7/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.