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What is the limit of #(4x)/(x-6)+(5x)/(x+6)# as x approaches infinity?

Answer 1

Ezra Adams

The limit is #9#

#lim_(xrarroo)(4x)/(x-6) = lim_(xrarroo)(4x)/(x(1-6/x)) #

# = lim_(xrarroo)(4)/((1-6/x)) = 4/(1-0) = 4#

And

#lim_(xrarroo)(5x)/(x+6) = lim_(xrarroo)(5x)/(x(1+6/x)) #

# = lim_(xrarroo)(5)/((1+6/x)) = 5/(1+0) = 5#

Therefore,

#lim_(xrarroo)((4x)/(x-6) + (5x)/(x+6)) = lim_(xrarroo)(4x)/(x-6) + lim_(xrarroo)(5x)/(x+6) #

# = 4+5=9#

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Answer 2

Adam Adkins

The limit of (4x)/(x-6)+(5x)/(x+6) as x approaches infinity is 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.