What is the limit as x approaches infinity of #e^(-x^2)#?
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The limit as x approaches infinity of e^(-x^2) is 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the limit of #[3 + 4/x - 5/x^2 + [x-1]/[x^3+1]# as x goes to infinity?
- How do you find the limit #(3+x^(-1/2)+x^-1)/(2+4x^(-1/2))# as #x->0^+#?
- How do you find the x values at which #f(x)=x/(x^2+1)# is not continuous, which of the discontinuities are removable?
- How do you evaluate the limit #(sinxcosx)/x# as x approaches #0#?
- For what values of x, if any, does #f(x) = 1/((x-2)(x+2)(e^x-3)) # have vertical asymptotes?

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