What is the limit as x approaches 0 of #tan(6x)/sin(2x)#?
The answer is 3:
How did I get there?
Let's apply this rule to our problem.
Now, all we need to do is combine both of them.
And there you have your final answer. Let me know if anything is not clear. I hope this helped.
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By de Moivre's theorem:
Equating imaginary parts:
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The limit as x approaches 0 of tan(6x)/sin(2x) is 3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How can I evaluate #lim_(x->0) (sinx-x)/x^3# without using L'Hopital's rule?
- #lim_(x rarr 4) (3 - sqrt(5 + x))/(1- sqrt(5 - x)) = ?#
- What is the limit of # (1/2x+3)# as x approaches infinity?

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