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What is the limit as x approaches 0 of #sin^2(x) 4x#?

Answer 1

It's #0#.

This is a continuous function, which means that there isn't an #x# value for which the #y# value doesn't exist. The limit of continuous functions is simply the function value, the #y# value:

#lim_{x \to 0} sin^2(x)4x = sin^2(0)*4*0 = 0#

So the limit is equal to 0.
Take a look at the function.

Here you can also see that te answer is 0.

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Answer 2

Elijah Abram

The limit as x approaches 0 of sin^2(x) 4x is 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.