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What is the limit as x approaches 0 of #5x^4+8x^2#?

Answer 1

Paisley Johnson

The limit is #0#.

Simply plug in zero for #x#:

#color(white)=lim_(xrarr0) 5x^4+8x^2#

#=5(0)^4+8(0)^2#

#=5*0+8*0#

#=0+0#

#=0#

You can take a look at the graph of the function and verify this:

graph{5x^4+8x^2 [-1, 1, -1.1, 1.1]}

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Answer 2

Axel Alvarez

The limit as x approaches 0 of 5x^4 + 8x^2 is 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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