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What is the Lewis structure of N2O?

Answer 1

Well, we got 16 valence electrons....

16 electrons of valence:

#2xx5_"nitrogen"+1xx6_"oxygen"="8 electron pairs"#

...to divide among three centers. Given the example, there will be formal charge separation. You just need to KNOW that the oxygen is terminal at this point.

#N-=stackrel(+)N-O^(-)# versus #""^(-)N=stackrel(+)N=O#

When we take into account the data, such as the bond lengths of nitrous oxide, oxygen, and dinitrogen, this is only half the story.

#N-=N# #:"bond length"=1.10xx10^-10*m#

#O=O# #:"bond length"=1.21xx10^-10*m#

#N-=stackrel+N-O^(-)# #:"N-O bond length"=1.19xx10^-10*m#

#:"N-N bond length"=1.13xx10^-10*m#

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Answer 2

Nicholas Antonuccio

The Lewis structure of N2O consists of a central nitrogen atom bonded to two oxygen atoms. The nitrogen atom shares one electron with each oxygen atom, forming a single bond with each oxygen atom. Additionally, each oxygen atom has two lone pairs of electrons. Therefore, the Lewis structure of N2O can be represented as N≡N-O.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.