What is the kinetic energy of an object with a mass of #1 kg# that has been in freefall for #1 s#?

Answer 1

#48.02# Joules

Kinetic energy (#KE#) is given by #(m.v^2)/2#, where #m# is mass in kg and #v# is velocity in meters. As the object of mass #1# kg undergoes free fall for #1# second, its velocity at the end of one second is given by #v=g*t#, where #g# is #9.8# #m/s^2# i.e.

#v=9.8*1=9.8# #m/s#, and hence #KE# is given by

#1/2*9.8^2 = 48.02# Joules.

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Answer 2

Xavier Adame

The kinetic energy of an object can be calculated using the formula:

Kinetic energy = (1/2) * mass * velocity^2

In freefall near the Earth's surface, the velocity of an object is approximately equal to the acceleration due to gravity multiplied by the time in freefall. The acceleration due to gravity is approximately 9.8 m/s^2.

So, the velocity of the object after 1 second of freefall is:

velocity = gravity * time velocity = 9.8 m/s^2 * 1 s velocity = 9.8 m/s

Now, substitute the mass and velocity into the kinetic energy formula:

Kinetic energy = (1/2) * 1 kg * (9.8 m/s)^2 Kinetic energy = (1/2) * 1 kg * 96.04 m^2/s^2 Kinetic energy ≈ 48.02 Joules

Therefore, the kinetic energy of the object after 1 second of freefall is approximately 48.02 Joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.