# What is the inverse of #h(x)=-4/x^2#?

##
The furthest I got on this question was #y=sqrt(-1/4x#

But I don't think that's right

The furthest I got on this question was

But I don't think that's right

Do you want + or -?

Exchange x and y.

Divide by x, then take the root.

By signing up, you agree to our Terms of Service and Privacy Policy

The inverse of h(x) = -4/x^2 is g(x) = ± √(-4/x), where x ≠ 0.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you identify all asymptotes or holes for #f(x)=(3x^2-2x-17)/(x-3)#?
- How do you find vertical, horizontal and oblique asymptotes for #(-4x^2 + 8x + 60)/(x^2- 4)#?
- How do you determine if #f(x)=x+absx# is an even or odd function?
- How do you identify all asymptotes or holes for #f(x)=(-x+1)/(x+4)#?
- How do you find the horizontal asymptote for # f(x) = (x+1) / (x+2)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7