# What is the interval of convergence of the MacClaurin series of #f(x)=1 / (3-2x)#?

To determine the MacLaurin's series for:

and we can see that in general:

so:

So the MacLaurin series is:

or:

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The interval of convergence for the Maclaurin series of ( f(x) = \frac{1}{3 - 2x} ) is ( |x| < \frac{3}{2} ).

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