What is the interval of convergence of #sum [(-1)^n(2^n)(x^n)] #?
By signing up, you agree to our Terms of Service and Privacy Policy
The interval of convergence for the series ( \sum{(-1)^n 2^n x^n} ) is ((-1/2, 1/2)).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you use a power series to find the exact value of the sum of the series #1+2+4/(2!) +8/(3!) +16/(4!) + …# ?
- How do you find the maclaurin series expansion of #(e^x-1)/x#?
- How do you find the interval of convergence #Sigma (3^n+4^n)x^n# from #n=[0,oo)#?
- What is the interval of convergence of #sum {(x - 7)^n}/{(7)^n}#?
- What is the radius of convergence of the MacLaurin series expansion for #f(x)= 1/sin x#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7