What is the integral of #sqrt(1-x^2)#?
Hint: First, apply trigonometric substitution. This question is in the form
You will have to use the half-angle identity after.
Integrate. You will get an indefinite integral.
Set up a right triangle to find the value for the indefinite integral.
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The integral of sqrt(1-x^2) is equal to (1/2)(xsqrt(1-x^2) + arcsin(x)) + C, where C is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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