What is the integral of sinh(3x)-cosh(4x)dx?

Answer 1

Evelyn Agard

The answer is #=1/3cosh(3x)-1/4sinh(4x)+C#

We need

#intsinhxdx=coshx+C#

#intcoshxdx=sinhx+C#

Therefore,

#int(sinh(3x)-cosh(4x))dx=intsinh(3x)dx-intcosh(4x)dx#

#=1/3cosh(3x)-1/4sinh(4x)+C#

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Answer 2

Emma Aldridge

The integral of sinh(3x) - cosh(4x) with respect to x is:

(1/3) * cosh(3x) - (1/4) * sinh(4x) + C

Where C is the constant of integration.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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