# What is the integral of #int tan^2(x)sec^4(x)#?

Rewriting one:

By signing up, you agree to our Terms of Service and Privacy Policy

The integral of (\int \tan^2(x) \sec^4(x) , dx) is (\frac{1}{3}\sec^3(x) + \frac{1}{3}\sec(x) + C), where (C) is the constant of integration.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the integral of # [ (1+cos^2(x)) / sin(x) ] dx#?
- How do you find the antiderivative of #f(x)=10/x^9#?
- How to calculate this limit? f:[0,1]#->RR#,f(x)=x#sqrt(1-x^2)# Calculate #lim_(x->0)1/x^2int_0^xf(t)dt#
- How do you find the indefinite integral of #int (x^2-4)/x#?
- What is the net area between #f(x) = x+8 # and the x-axis over #x in [2, 4 ]#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7