What is the integral of #int sec^3(x)dx#?
Here,
Using Integration by parts:
By signing up, you agree to our Terms of Service and Privacy Policy
The integral of (\int \sec^3(x) , dx) is equal to (\frac{1}{2} (\sec(x) \tan(x) + \ln|\sec(x) + \tan(x)|) + C), where (C) is the constant of integration.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you integrate #secx^4 dx#?
- How do you find the antiderivative of #sin^3(x) cos^2(x) dx#?
- How do you find the definite integral for: #sqrt(4+3(t^4))dt # for the intervals #[1, 4]#?
- How do you evaluate the definite integral #int 1+sinx# from #[pi/4, pi/2]#?
- How do you evaluate the definite integral #int (x^3+x-6)dx# from [2,4]?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7