# What is the integral of #e^(-0.2t) dt#?

Two methods:

Substitution

Check the answer by differentiating.

Learn the rule

(Verify be differentiating.)

So

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The integral of ( e^{-0.2t} ) with respect to ( t ) is:

[ \int e^{-0.2t} dt = -\frac{1}{0.2} e^{-0.2t} + C ]

Where ( C ) is the constant of integration. Therefore, the integral is:

[ -\frac{1}{0.2} e^{-0.2t} + C ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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