# What is the Horizontal Asymptote of #y=arctan(x)#?

By signing up, you agree to our Terms of Service and Privacy Policy

The horizontal asymptote of y=arctan(x) is y= -π/2 and y= π/2.

By signing up, you agree to our Terms of Service and Privacy Policy

- How do you evaluate the limit #cos((pix)/3)# as x approaches #2#?
- How do you find the limit of #(arctan(5x))/(sin(7x))# as x approaches 0?
- How do you find the limit #lnx/sqrtx# as #x->oo#?
- What is the limit of #(x-1)(x-2)(x-3)(x-4)(x-5)/(5x-1)^5# as x goes to infinity?
- How do you evaluate the limit #(x^2-x-6)/(x+2)# as x approaches #oo#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7