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What is the gravitational potential energy of a 93.0 kg sky diver who 550 m above the ground?

Answer 1

Sebastian Acosta

#501270# joules

Gravitational potential energy is given by the equation:

#"GPE"=mgh#

where:

#m# is the mass of the object in kilograms

#g# is the gravitational acceleration, which is #9.8 \ "m/s"^2# on Earth

#h# is the height risen in meters

So, we get:

#"GPE"=93 \ "kg"*9.8 \ "m/s"^2*550 \ "m"#

#=501270 \ "kg m"^2"/s"^2#

#=501270 \ "J"#

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Answer 2

Isabella Alvarez

The gravitational potential energy of a 93.0 kg sky diver who is 550 m above the ground is approximately 508,950 joules.

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Answer 3

Carson Alexander

The gravitational potential energy of the skydiver can be calculated using the formula: ( PE = mgh ), where ( m ) is the mass of the skydiver (93.0 kg), ( g ) is the acceleration due to gravity (9.8 m/s²), and ( h ) is the height above the ground (550 m). Substituting the given values into the formula:

( PE = (93.0 kg) \times (9.8 m/s^2) \times (550 m) )

( PE = 510,630 J )

So, the gravitational potential energy of the skydiver is 510,630 Joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.