What is the freezing point of a nonionizing antifreeze solution containing 388g ethylene glycol #C_2H_6O_2# and 409 g of water?

Answer 1

The freezing point = # - 28.42^oC#

#∆T_b# =# i*K_f*m#
mass of ethylene = #388 g#
molar mass =# 62.07# #g#/#mol#
no. of moles = #388#/#62.07# = #6.25# moles
mass of solvent = #409 g# = #0.409 kg#
molality = #6.25# moles/#0.409 kg# = #15.28 m#
#i #= #1#
#T_i# =# 0^oC#
#K_f#= #1.86^ oC/m#

Therefore,

#∆T_f = i*K_f*m# #∆T_f = 1.86^oC/m xx 15.28 m#
#∆T_f = 28.42^o C#
#T_f = 0^oC - 28.42^ oC = -28.42^ oC#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

The freezing point of the solution can be calculated using the formula:

ΔTf = Kf * m

Where: ΔTf = Freezing point depression Kf = Cryoscopic constant (for water, it is 1.86 °C/m) m = Molality of the solution (moles of solute per kilogram of solvent)

First, calculate the molality (m) of the solution:

  1. Calculate the moles of ethylene glycol (C2H6O2):

    • Moles of ethylene glycol = Mass of ethylene glycol / Molar mass of ethylene glycol
  2. Calculate the total mass of the solution:

    • Total mass = Mass of ethylene glycol + Mass of water
  3. Calculate the molality (m) of the solution:

    • Molality (m) = Moles of ethylene glycol / (Total mass of solution in kg)

Once you have the molality (m), plug it into the formula along with the cryoscopic constant (Kf) for water to find the freezing point depression (ΔTf).

Finally, subtract the freezing point depression (ΔTf) from the normal freezing point of water (0°C) to find the freezing point of the solution.

You can also use the equation: ΔTf = i * Kf * m

Where "i" is the van't Hoff factor, which is 1 for ethylene glycol since it does not ionize in solution.

Would you like to proceed with the calculations or need further clarification?

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7