What is the formula weight of #Mg(BrO_4)_2#?

Question

Ellie Andrews · Accepted Answer

#312.11 g/"mol"#

The formula weight of magnesium perbromate can be obtained by using the following equation:

atomic weight of element #xx#number of atoms given by subscript #=# formula mass

First, you want to have a periodic table available so you can determine the atomic weight of Mg, Br, and O:

There is one magnesium atom, so the atomic mass of Mg is just 24.31 g/mol

From the chemical formula, we have 2 bromine atoms. Therefore, the atomic mass has to be multiplied by 2 to obtain an atomic weight of 159.80 g/mol.

There are 8 oxygen atoms, so the atomic mass has to be multiplied by 8, which gives you a value of 128.00 g/mol

Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:

#color(magenta) ("24.31 g/mol + 159.80 g/mol + 128.00 g/mol = 312.11 g/mol")#

Cooper Adams · Answer

undefined To calculate the formula weight of Mg(BrO₄)₂, you need to determine the atomic weights of each element in the compound and then multiply them by the respective subscripts in the chemical formula.

The atomic weight of Mg (Magnesium) is approximately 24.305 g/mol, Br (Bromine) is approximately 79.904 g/mol, and O (Oxygen) is approximately 15.999 g/mol.

So, the formula weight of Mg(BrO₄)₂ is:

Mg: 1 * 24.305 = 24.305 g/mol
Br: 2 * 79.904 = 159.808 g/mol
O: 8 * 15.999 = 127.992 g/mol

Total: 24.305 + 159.808 + 127.992 = 312.105 g/mol