What is the formula mass for #Sr(NO_3)_2#?
First, you want to have a periodic table available so you can determine the atomic weight of Sr, N, and O:
From the chemical formula, we have 1 strontium atom, so the atomic weight of Sr is just 87.62 g/mol.
There are 2 nitrogen atoms, so the atomic mass has to be multiplied by 2, which gives you a value of 28.02 g/mol
Next, you have 6 oxygen atoms, so you would multiply the atomic mass of O by 6 to obtain an atomic weight of 96.00 g/mol
Now you want to add the mass of each atom together to obtain the formula mass of the entire compound:
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To calculate the formula mass of Sr(NO₃)₂, you need to find the atomic masses of each element in the compound and then multiply them by the respective subscript in the formula.
Sr: 1 atom * 87.62 g/mol = 87.62 g/mol N: 2 atoms * 14.01 g/mol = 28.02 g/mol O: 6 atoms * 16.00 g/mol = 96.00 g/mol
Total formula mass = 87.62 g/mol + 28.02 g/mol + 96.00 g/mol = 211.64 g/mol
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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