What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec2? And How do I draw a Free Body Diagram of this?
The only force on it is its weight,
The only force acting on it is its weight, w, as it is falling freely.
Draw an elevator cage with a downward force of 9800 N to create a free body diagram (I'm sure you'd get a lot of points for drawing it in such detail).
Hope this is helpful, Steve.
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The force on the elevator is its weight, given by the formula F = m * g, where m is the mass (1000 kg) and g is the acceleration due to gravity (9.8 m/s^2).
To draw a Free Body Diagram:
- Represent the elevator as a box.
- Draw an arrow pointing downward from the center of the box to indicate the force of gravity (mg).
- If there are other forces involved, like tension in a cable, represent them with additional arrows. In this case, only gravity is acting.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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