# What is the force, in terms of Coulomb's constant, between two electrical charges of #22 C# and #-32 C# that are #6 m # apart?

It is an attraction force of

Coulomb's Law expressed as an equation is

If the value of F is negative, the force is one of attraction; otherwise, it is one of repulsion.

I apologize for the editing that was necessary; I had not noticed at first that the response was to be in terms of k."

Hope this is helpful, Steve.

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The force between two electrical charges can be calculated using Coulomb's law:

(F = \frac{{k \cdot |q_1 \cdot q_2|}}{{r^2}})

Where:

- (F) is the force between the charges,
- (k) is Coulomb's constant ((8.9875 \times 10^9 , \text{N m}^2/\text{C}^2)),
- (q_1) and (q_2) are the magnitudes of the charges, and
- (r) is the distance between the charges.

Plugging in the given values:

(F = \frac{{(8.9875 \times 10^9) \cdot |22 , \text{C} \cdot (-32 , \text{C})|}}{{(6 , \text{m})^2}})

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