# What is the force, in terms of Coulomb's constant, between two electrical charges of #-2 C# and #4 C# that are #6 m # apart?

The force would be attractive, and equal in magnitude to

With the values given in this question, the force becomes

The negative sign tells us the force is attractive.

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The force between the two charges is 6.67 × 10^-11 N, calculated using Coulomb's law: F = k * (|q1 * q2| / r^2), where k is Coulomb's constant (8.9875 × 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges (-2 C and 4 C), and r is the distance between the charges (6 m).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How much power is produced if a voltage of #6 V# is applied to a circuit with a resistance of #42 Omega#?
- What is the electric current produced when a voltage of #24 V# is applied to a circuit with a resistance of #32 Omega#?
- If a current of #8 A# passing through a circuit generates #4 W# of power, what is the resistance of the circuit?
- How much power is produced if a voltage of #3 V# is applied to a circuit with a resistance of #3 Omega#?
- What occurs when two charges are moved closer together?

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