What is the equilibrium constant of #PCl_5 (g) - PCl_3(g) + Cl_2(g)#?

Question

What is the equilibrium constant of #PCl_5 (g) -> PCl_3(g) + Cl_2(g)#?

Naomi Aronson · Accepted Answer

Here's what I got.

In fact, there are two ways to express the equilibrium constant because you are working with a gas-filled reaction. One expression will feature molar concentrations and it will give you the value of #K_c#, while the other will feature partial pressures and give you the value of #K_p#. Thus, this is how your equilibrium reaction appears. #"PCl"_ (5(g)) rightleftharpoons "PCl"_ (3(g)) + "Cl"_ (2(g))# Now, the expression for #K_c# is given by the ratio that exists between the equilibrium concentrations of the products raised to the power of their respective stoichiometric coefficients and the equilibrium concentrations of the reactants raised to the power of their respective stoichiometric coefficients. Here, you've #K_c = (["PCl"_3] * ["Cl"_2])/(["PCl"_5]# The expression for #K_p# is given by the ratio that exists between the equilibrium partial pressures of the products raised to the power of their respective stoichiometric coefficients and the equilibrium partial pressures of the reactants raised to the power of their respective stoichiometric coefficients. Here, you've #K_p = (("PCl"_3) * ("Cl"_ 2))/(("PCl"_5))#

Henry Antrim · Answer

undefined The equilibrium constant (Kc) for the reaction PCl5(g) -> PCl3(g) + Cl2(g) is given by the expression:

Kc = [PCl3] * [Cl2] / [PCl5]

Where [PCl3], [Cl2], and [PCl5] represent the molar concentrations of PCl3, Cl2, and PCl5, respectively, at equilibrium.

Since the stoichiometry of the reaction is 1:1:1, the expression simplifies to:

Kc = [PCl3] * [Cl2] / [PCl5] = (x * x) / (initial concentration of PCl5 - x)

Where x represents the change in concentration at equilibrium.

The equilibrium constant depends on the temperature at which the reaction occurs. Without specific temperature information, the equilibrium constant for the reaction cannot be determined.

What is the equilibrium constant of #PCl_5 (g) -&gt; PCl_3(g) + Cl_2(g)#?

What is the equilibrium constant of #PCl_5 (g) -> PCl_3(g) + Cl_2(g)#?