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What is the equilibrium constant for the following reaction at #"298 K"#? And what is the partial pressure of #"S"_8(g)# above #"S"(s, "orthorhombic")# at equilibrium at #25^@ "C"#?

#8 "S"(s,"orthorhombic") rightleftharpoons "S"_8(g)#

Answer 1

Olivia Anton

You will have to review this question. Sulfur is a solid at room temperature, with a low vapour pressure.

The normal boiling point of sulfur is #444.6# #""^@C#.

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Answer 2

Wyatt Adkins

The equilibrium constant (K) for the reaction at 298 K is (K = [S_8(g)]). The partial pressure of (S_8(g)) above (S(s, \text{orthorhombic})) at equilibrium at 25°C is 1 atm.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.