# What is the equation of the tangent line of #f(x)=x^3+2x^2-3x+2# at #x=1#?

Step 1: Determine the equation's derivative

Step 4: Use the point slope formula to find the tangent line's equation.

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The equation of the tangent line of f(x)=x^3+2x^2-3x+2 at x=1 is y = 6x - 3.

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