What is the equation of the tangent line of # f(x)=(x-1)^2 # at # x=3 #?
The gradient of the tangent to a curve at any particular point is give by the derivative of the curve at that point.
so If
#dy/dx = 2x-2#
When So the tangent we seek passes through We can confirm this solution is correct graphically:
and
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The equation of the tangent line of f(x)=(x-1)^2 at x=3 is y = 8x - 23.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- Find all of the points on the curve #y = x^3 + 5x^2# where the tangent line is parallel to the line #y = 11x − π#.?
- For #f(x)=x^4# what is the equation of the tangent line at #x=-1#?
- Can the slope of a tangent line be negative?

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