What is the equation of the tangent line of #f(x)=sqrt(x)# at #x=4#?
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The equation of the tangent line of f(x) = √(x) at x = 4 is y = (1/4)x + 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the equation of the line normal to #f(x)=4/(x^3-1) # at #x=0#?
- How do you find the derivative of #f(x)=1/x^2# using the limit process?
- What is the equation of the normal line of #f(x)= tanx# at #x = pi/8#?
- How do you find the equation of the line tangent to #y=x^3 - 2x# at the point (2,4)?
- What is the equation of the normal line of #f(x)=12x^3-4x^2-5x# at #x=-2#?

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