# What is the equation of the tangent line of #f(x)=sqrt(x+1) # at #x=0#?

and thus

The equation is present.

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The equation of the tangent line of f(x)=sqrt(x+1) at x=0 is y = 1/2x + 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- For #f(x)=x^2/sqrt(x^3-5)# what is the equation of the tangent line at #x=5#?
- What is the equation of the tangent line of #y=1/x^2# at #x=1#?
- How do you estimate the instantaneous rate of change at the point for #x=5# for #f(x) = ln(x)#?
- What is the equation of the tangent line for #sin(x)# at the point x=2?
- How do you find the derivative of #-5x^2+8x+2# using the limit definition?

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