What is the equation of the tangent line of #f(x)=ln(x+3)/x+7x# at #x=3#?

Answer 1

#y=(1-2ln6)/18x+(4ln6+125)/6#

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

Equation of the tangent line passing through the point #P-=(3,21.085)# with slope #m=-0.147# is given by
#0.147x+y-21.526=0#

#"We need to find the equation of the tangent line in the form "#
#px+qy+c=0# Given:
#f(x)=ln(x+3)/(7x)+7x# Let #y=f(x)# #y=ln(x+3)/(7x)+7x#
At #x=3, f(x)=f(3)=ln(3+3)/(7xx3)+7xx3=21.085#

Multiplying the functin with x

#xy=1/7ln(x+3)+7x^2#
#xy=7x^2+1/7ln(x+3)#

Differentiating wrt x on both sides

#xy'+y=1/7(1/(x+3))+14x#

Substituting for x and y

#3y'+21.085=1/7(1/(3+3))+14xx3#
Dividing throughout by 3 #y'+21.085=1/42+42, y'=1/42+42-21.085=20.938#
#y'+21.085=20.938#
#y'=-0.147# Slope of the tangent line is #m=-0.147#
Equation of the tangent line passing through the point #P-=(3,21.085)# with slope #m=-0.147# is given by
#(y-21.085)/(x-3)=-0.147#
#y-21.085=-0.147(x-3)# #y-21.085=-0.147x+0.440# #0.147x+y-21.085-0.440=0#
Equation of the tangent line passing through the point #P-=(3,21.085)# with slope #m=-0.147# is given by #0.147x+y-21.526=0#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To find the equation of the tangent line of f(x) = ln(x+3)/(x+7x) at x=3, we need to find the derivative of f(x) and evaluate it at x=3.

First, let's find the derivative of f(x) using the quotient rule:

f'(x) = [(x+7x)(1/(x+3)) - ln(x+3)(1+7)] / (x+7x)^2

Simplifying this expression, we get:

f'(x) = [(8x+1)/(x+3)^2] - [ln(x+3)(8)] / (x+7x)^2

Now, let's evaluate f'(x) at x=3:

f'(3) = [(8(3)+1)/(3+3)^2] - [ln(3+3)(8)] / (3+7(3))^2

Simplifying this expression, we get:

f'(3) = [25/36] - [ln(6)(8)] / 169

Therefore, the slope of the tangent line at x=3 is f'(3) = [25/36] - [ln(6)(8)] / 169.

To find the equation of the tangent line, we use the point-slope form:

y - f(3) = f'(3)(x - 3)

Now, substitute the values of f(3) and f'(3) into the equation:

y - [ln(3+3)/(3+7(3))] = [25/36] - [ln(6)(8)] / 169 * (x - 3)

Simplifying this equation, we get the equation of the tangent line of f(x) at x=3.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7