# What is the equation of the tangent line of #f(x) =cos2x+sin2x+tanx# at #x=pi/8#?

Hence equation of tangent is

Therefore, the tangent equation is

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The equation of the tangent line of f(x) = cos(2x) + sin(2x) + tan(x) at x = pi/8 is y = 1 + sqrt(2) + 2sqrt(2)(x - pi/8).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the equation of the tangent line of #f(x)=xsinx+cosx-tanx# at #x=-1#?
- What is the equation of the line tangent to #f(x)=2x-x^2 # at #x=0#?
- How do you find the horizontal and vertical tangents to #x = Cos(3t)# and #y = 2sin(t)#?
- How do you find the derivative of the function #f(x)=x^2-3x# using #f(x+h)-f(x)/h#?
- How do you determine the slope of a tangent line? Why does this work?

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