# What is the equation of the tangent line of #f(x)=(5+4x)^2 # at #x=7#?

The equation is

The tangent's equation is

graph{(y-264x+759)=0 [-299.3, 309.2, -83.8, 220.8]}-(y-(5+4x)^2)

By signing up, you agree to our Terms of Service and Privacy Policy

The equation of the tangent line of f(x)=(5+4x)^2 at x=7 is y = 64x - 896.

By signing up, you agree to our Terms of Service and Privacy Policy

- What is the equation of the line tangent to # f(x)=sqrt(e^x-x) # at # x=1#?
- How do you find the tangent line of #f(x) = 3-2x^2 # at x=-1?
- What is the derivative of #6 (3^(2x-1))#?
- How do you find the equation of the tangent line to the graph of #f(x)=sqrt(x-1)# at point #(5,2)#?
- How do you find the equation of the line tangent to #y=cosx# at x=π/4?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7