What is the equation of the tangent line of #f(x)=(2x)/(x+1)^2 # at #x=0#?
The tangent is
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The equation of the tangent line of f(x)=(2x)/(x+1)^2 at x=0 is y = 0.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the equation of the line normal to #f(x)=x ^3-3x^2 # at #x=4#?
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- What is the equation of the line with slope #3# which is tangent to the curve #f(x)=7x-x^2#?
- What is the equation of the tangent line of #f(x)=2x^2+xe^x# at #x=5#?
- What is the average value of the function #f(x)=e^4x^2# on the interval #[-1/4,1/4]#?

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