# What is the equation of the normal line of #f(x)= xln(1/x^2)# at #x = 2#?

Verify this using the graph below: graph{(y-xln(1/x^2))(y-x/(2ln(2)+2)+1/(ln(2)+1)+4ln(2))=0 [-10, 10, -5, 5]}

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The equation of the normal line of f(x) = xln(1/x^2) at x = 2 is y = -4x + 4ln(4).

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