What is the equation of the normal line of #f(x)=xe^(1/x)-x^2-3# at #x=0#?
Luke AlvarezThat function is not defined at
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Ezekiel AlexanderThe equation of the normal line of f(x)=xe^(1/x)-x^2-3 at x=0 is y = -3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the equation of the tangent line of #f(x) =x/(x-2e^x)+x/e^x-x# at #x=3#?
- How do you find the slope of the line tangent to #x^2-y^2=3# at (2,1), (2,-1), (sqrt3,0)?
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- What is the equation of the normal line of #f(x)=-2x^3+4x^2+2x# at #x=-1#?
- How do you find the equation of the tangent line when x = 1, include the derivative of #Y= arctan(sqrtx)#?
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