# What is the equation of the normal line of #f(x)=x^3-4x^2+7x# at #x=-2#?

We need the negative reciprocal of slope m and the point

Let us now solve for the normal line

#y=-1/35(x+2)-38

God bless....I hope the explanation is useful.

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The equation of the normal line of f(x)=x^3-4x^2+7x at x=-2 is y = -5x - 3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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