# What is the equation of the normal line of #f(x)=(x-1)(x-3)(x+2) # at #x=3 #?

Given:

So the point of intersection is going to be at

Expanding the given equation we get

So

And at

Therefore the slope of the normal will be

Using the slope-point form for the normal we have

which can be simplified as

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The equation of the normal line of f(x)=(x-1)(x-3)(x+2) at x=3 is y = -4x + 15.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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