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What is the equation of the line with slope # m= 9/14 # that passes through # (-3,1) #?

Answer 1

14y - 9x -41 = 0

An example of a straight line's equation is

The equation is y - b = m(x - a), where m is the gradient and (a, b) is a point on the line. The values of m and (a, b) = (-3. 1) are known.

# x + 3 - 1 = 9/14 #y

Add 14 to both sides to get rid of the fraction.

Consequently, 14y-14 = 9x + 27

At the end, 14y - 9x - 41 = 0.

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Answer 2

Jace Anderson

The equation of the line with slope m = 9/14 that passes through the point (-3,1) can be found using the point-slope form of a linear equation.

The point-slope form of a linear equation is: y - y₁ = m(x - x₁)

where:

(x₁, y₁) are the coordinates of the given point.
m is the slope of the line.

Substituting the given values into the formula: y - 1 = (9/14)(x + 3)

Now, you can simplify this equation to find the slope-intercept form (y = mx + b), if needed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.