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What is the equation of the line with slope # m= -7/8 # that passes through # (2,5) #?

Answer 1

Kennedy Adams

#y=-7/8x+54/5#

#m=-7/8" slope"#

#P=(2,5)" any point on the line"#

#x_1=2" ; "y_1=5#

#"Apply the formula :"#

#y-y_1=m(x-x_1)#

#y-5=-7/8(x-2)#

#y=-7/8x+14/8+5#

#y=-7/8x+(14+40)/5#

#y=-7/8x+54/5#

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Answer 2

Savannah Anderson

The equation of the line with slope (m = -\frac{7}{8}) that passes through the point ((2, 5)) can be found using the point-slope form of the equation of a line:

(y - y_1 = m(x - x_1))

Substitute the values of the slope (m = -\frac{7}{8}) and the point ((x_1, y_1) = (2, 5)) into the equation:

(y - 5 = -\frac{7}{8}(x - 2))

Simplify the equation:

(y - 5 = -\frac{7}{8}x + \frac{7}{4})

Add 5 to both sides:

(y = -\frac{7}{8}x + \frac{7}{4} + 5)

Combine the constants:

(y = -\frac{7}{8}x + \frac{17}{4})

Therefore, the equation of the line with slope (m = -\frac{7}{8}) that passes through the point ((2, 5)) is (y = -\frac{7}{8}x + \frac{17}{4}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.